7.1.1: Recursive Formulas
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 14782
Describing the Pattern and Writing a Recursive Rule for a Sequence
In 2013, the days a full moon appeared were in the following sequence (with Jan. 1 being Day 1). Write a recursive formula for the sequence.
9, 38, 67, 96, ...
Source: Moongiant
Recursive Rule
A recursive rule for a sequence is a formula which tells us how to progress from one term to the next in a sequence. Generally, the variable \(\ n\) is used to represent the term number. In other words, \(\ n\) takes on the values 1 (first term), 2 (second term), 3 (third term), etc. The variable, \(\ a_{n}\) represents the \(\ n^{t h}\) term and \(\ a_{n1}\) represents the term preceding \(\ a_{n}\).
Example sequence: \(\ 4,7,11,16, \ldots, a_{n1}, a_{n}\)
In the above sequence, \(\ a_{1}=4\), \(\ a_{2}=7\), \(\ a_{3}=11\) and \(\ a_{4}=16\).
Let's describe the pattern and write a recursive rule for the sequence: 9,11,13,15,…
First we need to determine what the pattern is in the sequence. If we subtract each term from the one following it, we see that there is a common difference of 29. We can therefore use \(\ a_{n1}\) and \(\ a_{n}\) to write a recursive rule as follows: \(\ a_{n}=a_{n1}+29\)
Now, let's write a recursive rule for the following sequences.

3,9,27,81,…
In this sequence, each term is multiplied by 3 to get the next term. We can write a recursive rule: \(\ a_{n}=3 a_{n1}\)

1,1,2,3,5,8,…
This is a special sequence called the Fibonacci sequence. In this sequence each term is the sum of the previous two terms. We can write the recursive rule for this sequence as follows: \(\ a_{n}=a_{n2}+a_{n1}\).
Examples
Example 1
Earlier, you were asked to write a recursive formula for the sequence 9, 38, 67, 96, ...
Solution
First we need to determine what pattern the sequence is following. If we subtract each term from the one following it, we find that there is a common difference of 29. We can therefore use \(\ a_{n1}\) and \(\ a_{n}\) to write a recursive rule as follows: \(\ a_{n}=a_{n1}+29\)
Write the recursive rules for the following sequences.
Example 2
1, 2, 4, 8, …
Solution
In this sequence each term is double the previous term so the recursive rule is: \(\ a_{n}=2 a_{n1}\)
Example 3
1, −2, −5, −8, …
Solution
This time three is subtracted each time to get the next term: \(\ a_{n}=a_{n1}3\)
Example 4
1, 2, 4, 7, …
Solution
This one is a little trickier to express. Try looking at each term as shown below:
\(\ \begin{array}{l}
a_{1}&=1 \\
a_{2}&=a_{1}+1 \\
a_{3}&=a_{2}+2 \\
a_{4}&=a_{3}+3 \\
&\vdots \\
a_{n}&=a_{n1}+(n1)
\end{array}\)
Review
Describe the pattern and write a recursive rule for the following sequences.
 \(\ \frac{1}{4},\frac{1}{2}, 1,2\) …
 5, 11, 17, 23, …
 33, 28, 23, 18, …
 1, 4, 16, 64, …
 21, 30, 39, 48, …
 100, 75, 50, 25, …
 243, 162, 108, 72, …
 128, 96, 72, 54, …
 1, 5, 10, 16, 23, …
 0, 2, 2, 4, 6, …
 3, 5, 8, 12, …
 0, 2, 6, 12, …
 4, 9, 14, 19, …
 \(\ \frac{1}{2}, \frac{2}{3}, \frac{3}{4}, \frac{4}{5}\) …
 4, 5, 9, 14, 23, …
Answers for Review Problems
To see the Review answers, open this PDF file and look for section 11.2.
Vocabulary
Term  Definition 

common difference  Every arithmetic sequence has a common or constant difference between consecutive terms. For example: In the sequence 5, 8, 11, 14..., the common difference is "3". 
common ratio  Every geometric sequence has a common ratio, or a constant ratio between consecutive terms. For example in the sequence 2, 6, 18, 54..., the common ratio is 3. 
index  The index of a term in a sequence is the term’s “place” in the sequence. 
recursive  The recursive formula for a sequence allows you to find the value of the n^{th} term in the sequence if you know the value of the (n1)^{th} term in the sequence. 
recursive formula  The recursive formula for a sequence allows you to find the value of the n^{th} term in the sequence if you know the value of the (n1)^{th} term in the sequence. 
sequence  A sequence is an ordered list of numbers or objects. 