5.3: Square and Rectangle Area and Perimeter
- Page ID
- 2155
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\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)Compute edge and coverage measures of rectilinear quadrilaterals, given linear measures.
Area and Perimeter of Rectangles
To find the area of a rectangle, calculate \(A=bh\), where \(b\) is the base (width) and \(h\) is the height (length). The perimeter of a rectangle will always be \(P=2b+2h\).
![f-d_0c9a79962fc5723da8c0215d936990f9fea47b63d4511708daa10731+IMAGE_TINY+IMAGE_TINY.png](https://k12.libretexts.org/@api/deki/files/1728/f-d_0c9a79962fc5723da8c0215d936990f9fea47b63d4511708daa10731%252BIMAGE_TINY%252BIMAGE_TINY.png?revision=1&size=bestfit&width=450)
If a rectangle is a square, with sides of length s, then perimeter is \(P_{square}=2s+2s=4s\) and area is \(A_{sqaure}=s\cdot s=s^2\).
![f-d_7ca9b8bf62b2e92936dd2e410390a2f666a3a0eef8c17ea45ba02cf8+IMAGE_TINY+IMAGE_TINY.png](https://k12.libretexts.org/@api/deki/files/1729/f-d_7ca9b8bf62b2e92936dd2e410390a2f666a3a0eef8c17ea45ba02cf8%252BIMAGE_TINY%252BIMAGE_TINY.png?revision=1&size=bestfit&width=450)
What if you were given a rectangle and the size of its base and height? How could you find the total distance around the rectangle and the amount of space it takes up?
Example \(\PageIndex{1}\)
The area of a square is \(75\text{ in}^2\). Find the perimeter.
Solution
To find the perimeter, we need to find the length of the sides.
\(\begin{aligned} A&=s^2=75\text{ in}^2 \\ s&=\sqrt{75}=5\sqrt{3}\text{ in } \end{aligned}\)
From this, \(P=4(5\sqrt{3})=20\sqrt{3}\text{ in }\)
Example \(\PageIndex{2}\)
Draw two different rectangles with an area of \(36\text{ cm^2 }\).
Solution
Think of all the different factors of 36. These can all be dimensions of the different rectangles.
![f-d_a010a8c55e067fc941596fc82902aae27eb7d1d59bbd8bfa870e5573+IMAGE_TINY+IMAGE_TINY.png](https://k12.libretexts.org/@api/deki/files/1730/f-d_a010a8c55e067fc941596fc82902aae27eb7d1d59bbd8bfa870e5573%252BIMAGE_TINY%252BIMAGE_TINY.png?revision=1&size=bestfit&width=450)
Other possibilities could be \(6\times 6\), \(2\times 18\), and \(1\times 36\).
Example \(\PageIndex{3}\)
Find the area and perimeter of a rectangle with sides \(4\text{ cm }\) by \(9\text{ cm }\).
![f-d_feea629789b7999660f1e278d4abb1a454e6ffd1b9eceb308598ce40+IMAGE_TINY+IMAGE_TINY.png](https://k12.libretexts.org/@api/deki/files/1731/f-d_feea629789b7999660f1e278d4abb1a454e6ffd1b9eceb308598ce40%252BIMAGE_TINY%252BIMAGE_TINY.png?revision=1&size=bestfit&width=450)
Solution
The perimeter is \(4+9+4+9=26\text{ cm }\). The area is \(A=9\cdot 4=36\text{ cm}^2\).
Example \(\PageIndex{4}\)
Find the area and perimeter of a square with side \(5\text{ in }\).
Solution
The perimeter is \(4(5)=20\:in\) and the area is \(5^2=25\text{ in}^2\).
Example \(\PageIndex{5}\)
Find the area and perimeter of a rectangle with sides \(13\text{ m }\) and \(12\text{ m}^2\).
Solution
The perimeter is \(2(13)+2(12)=50\text{ m }\). The area is \(13(12)=156\text{ m}^2\).
Review
- Find the area and perimeter of a square with sides of length \(12\text{ in }\).
- Find the area and perimeter of a rectangle with height of \(9\text{ cm }\) and base of \(16\text{ cm }\).
- Find the area and perimeter of a rectangle if the height is 8 and the base is 14.
- Find the area and perimeter of a square if the sides are \(18\text{ ft }\).
- If the area of a square is \(81\text{ ft}^2\), find the perimeter.
- If the perimeter of a square is \(24\text{ in }\), find the area.
- The perimeter of a rectangle is 32. Find two different dimensions that the rectangle could be.
- Draw two different rectangles that haven an area of \(90\text{ mm}^2\).
- True or false: For a rectangle, the bigger the perimeter, the bigger the area.
- Find the perimeter and area of a rectangle with sides \(17\text{ in }\) and \(21\text{ in }\).
Vocabulary
Term | Definition |
---|---|
area | The amount of space inside a figure. Area is measured in square units. |
perimeter | The distance around a shape. The perimeter of any figure must have a unit of measurement attached to it. If no specific units are given (feet, inches, centimeters, etc), write units. |
Area of a Rectangle | To find the area '\(A\)' of a rectangle, calculate \(A = bh\), where \(b\) is the base (width) and h is the height (length). |
Perimeter of a Rectangle | The perimeter '\(P\)' of a rectangle is equal to twice the base added to twice the height: \(P = 2b + 2h\). |
Additional Resources
Interactive Element
Video: Determine the Area of a Rectangle Involving Whole Numbers
Activities: Area and Perimeter of Rectangles Discussion Questions
Study Aids: Triangles and Quadrilaterals Study Guide
Practice: Square and Rectangle Area and Perimeter
Real World: Perimeter